
Finding a basis of an infinite-dimensional vector space?
For many infinite-dimensional vector spaces of interest we don't care about describing a basis anyway; they often come with a topology and we can therefore get a lot out of studying dense …
Proof of infinite monkey theorem. - Mathematics Stack Exchange
Apr 24, 2015 · The infinite monkey theorem states that if you have an infinite number of monkeys each hitting keys at random on typewriter keyboards then, with probability 1, one of them will …
elementary set theory - What do finite, infinite, countable, not ...
What do finite, infinite, countable, not countable, countably infinite mean? [duplicate] Ask Question Asked 13 years, 3 months ago Modified 13 years, 3 months ago
calculus - Infinite Geometric Series Formula Derivation
Infinite Geometric Series Formula Derivation Ask Question Asked 12 years, 7 months ago Modified 4 years, 10 months ago
elementary set theory - What is the definition for an infinite set ...
Dec 3, 2020 · However, while Dedekind-infinite implies your notion even without the Axiom of Choice, your definition does not imply Dedekind-infinite if we do not have the Axiom of Choice …
infinity - What is the definition of an infinite sequence ...
May 12, 2024 · Except for $0$ every element in this sequence has both a next and previous element. However, we have an infinite amount of elements between $0$ and $\omega$, which …
How can Cyclic groups be infinite - Mathematics Stack Exchange
Oct 4, 2020 · I am a little confused about how a cyclic group can be infinite. To provide an example, look at $\\langle 1\\rangle$ under the binary operation of addition. You can never …
One divided by Infinity? - Mathematics Stack Exchange
Jul 15, 2015 · Infinite decimals are introduced very loosely in secondary education and the subtleties are not always fully grasped until arriving at university. By the way, there is a group …
If $S$ is an infinite $\sigma$ algebra on $X$ then $S$ is not …
6 Show that if a $\sigma$-algebra is infinite, that it contains a countably infinite collection of disjoint subsets. An immediate consequence is that the $\sigma$-algebra is uncountable.
Infinite Cartesian product of countable sets is uncountable
If the sets Ai A i are all countably infinite, then the product A A is also countably infinite. The argument is like this: if the product A A is countably infinite, then you can enumerate all of the …